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📅 March 10, 2026 👤 scraface

Mar 10, 2026

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9(x - 3)^2 - 81 - 16(y - 2)^2 + 64 = 71
9(x - 3)^2 - 16(y - 2)^2 = 88
Normalize the equation:
Divide the entire equation by 88:
\frac{9(x - 3)^2}{88} - \frac{16(y - 2)^2}{88} = 1
Simplifies to:
\frac{(x - 3)^2}{\frac{88}{9}} - \frac{(y - 2)^2}{\frac{88}{16}} = 1
The center of the hyperbola is \((h, k) = (3, 2)\).
Therefore, the center of the hyperbola is \(\boxed{(3, 2)}\).
A science policy analyst is evaluating a proposal involving the sum of...

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