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Home » Thus, $ p(x) = 2x^2 + x $. Then $ p(0) = 0 $. - IX Labs

Thus, $ p(x) = 2x^2 + x $. Then $ p(0) = 0 $. - IX Labs

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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First, simplify the expression \( R(x) = rac{x^2 - 1}{x + 1} \). Noti...
x^2 - 1 = (x - 1)(x + 1)
R(x) = rac{(x - 1)(x + 1)}{x + 1}
For \( x
e -1 \), we can cancel \( x + 1 \):
R(x) = x - 1
Now evaluate \( R(-2) \):
R(-2) = -2 - 1 = -3
Therefore, the reaction rate at \( x = -2 \) is:
oxed{-3}

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